what cvolume will 500 ml of gas at 20 c and a pressure of 420 mmhg occupy if the temperature is reduced to -80 c and the pressure is increased to 650 mmhg

Respuesta :

By using the combined gas law, the volume of the gas is found to be 212.81mL when the pressure and temperature is changed.

The Combined Gas Law combines the provisions of Charles Law, Boyle's Law, and Gay Lussac's Law. According to the Combined Gas Law, a gas pressure x temperature x volume = constant. The combined gas law is essentially a reworking of the ideal gas law, with both n (moles of gas) and R (already constant) remaining constant. It may be used to compute the conditions of the resultant system based on changes in pressure, temperature, or volume.

Given:

P1 = 420 mm Hg

V1 = 500mL

T1 = 20℃ = 20 + 273 = 293K

P2 = 650 mm Hg

T2 = -80℃ = -80 + 273 = 193K

To find:

V2 = ?

Formula:

P1V1 / T1 = P2V2 / T2

Calculations:

V2 = P1V1T2 / T1P2

V2 = 420 x 500 x 193 / 293 x 650

V2 = 212.81mL

Result:

The volume of the gas is found to be 212.81mL

Learn more about the combined gas law here:

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