Respuesta :
The empirical formula of mesitylene is C₃H₄.
To solve this problem, we need to determine the molar ratio of carbon and hydrogen in mesitylene. We can do this by first calculating the masses of carbon and hydrogen in the sample. Because all the carbon in mesitylene is transformed into carbon dioxide, the mass of carbon in CO₂ will be equal to the mass of carbon in the mesitylene. All we need is the molar mass of carbon dioxide: 44 g/mol
12 g of carbon : 44 g of carbon dioxide = X : 0.379 g of carbon dioxide
X = 12 g of carbon * 0.379 of carbon dioxide / 44 g of carbon dioxide
X = 0.103 g of carbon
Because mesitylene is composed of just carbon and hydrogen, we can determine the mass of hydrogen by subtracting the mass of carbon from the mass of mesitylene:
0.115 g - 0.103 g = 0.012 g of hydrogen
Now we divide these masses by the molar masses of the elements:
0.103 g / 12 g/mol =0.009 mol of carbon
0.012 g / 1 g/mol = 0.012 mol of hydrogen
We divide the moles by the smaller of the two numbers to get the molar ratio:
0.009 mol / 0.009 mol = 1 for carbon
0.012 mol / 0.009 mol = 1.33 for hydrogen
Because we need the molar ratio to be in integers, we multiply both values by 3:
1 * 3 = 3 for carbon
1.33 * 3 = 4 for hydrogen
This means that the empirical formula of mesitylene is C₃H₄.
You can learn more about empirical formulas here:
brainly.com/question/14425592
#SPJ4
