The value of k will be positive for a graph with a y-intercept larger than 2,
and k will be negative for a graph having a y-intercept lesser than 2.
Reasons:
The transformation of a function addition of a constant value, k, to the y-
value, move the graph of the function k-units up if k is positive, and k-units
down if k is negative;
The given function f(x) = 2·x + 1
The graph of the function f(x) + k, where k = 5 we get;
Graph of function = f(x) + 5, which gives;
[tex]\begin{array}{|c|c|c|}\underline{x}&\underline{f(x)}&\underline{g(x) = f(x) + 5}\\0&1&6\\1&3&8\\2&5&10\\3&7&12\\4&9&14\\5&11&16\end{array}\right][/tex]
Where, k is negative, and k = -3 for example, we get;
Graph of function = f(x) - 3, which gives;
[tex]\begin{array}{|c|c|c|}\underline{x}&\underline{f(x)}&\underline{g(x) = f(x) - 3}\\0&1&-3\\1&3&0\\2&5&2\\3&7&4\\4&9&6\\5&11&8\end{array}\right][/tex]
Therefore, the value of k is positive if the graph is lifted higher than the f(x)
and the value of k is negative if the graph is shifted downwards.
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https://brainly.com/question/17422677
