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Imagine that you have two black dogs. One is black because it carries two dominant genes for black (BB). The other is black because it carries one dominant gene for black and one recessive gene for the recessive color liver (Bb). Use a Punnett square to predict the phenotype and genotype for the offspring of a cross between these two dogs.

Imagine that you have two black dogs One is black because it carries two dominant genes for black BB The other is black because it carries one dominant gene for class=

Respuesta :

Phenotype- 100 percent black
Genotype- BB and Bb

Answer:

The correct answer would be:

  • Genotype: BB and Bb
  • Phenotype: Black color

Black is a dominant trait as it is expressed in heterozygous condition (Bb).

The genotype of one parent is BB. Thus, it would produce only one type of gamete that is, B.

The genotype of other parent is Bb. It would produce two types of gametes; B and b.

The cross will result in the production of puppies with two types of genotypes BB and Bb.

However, the phenotype of all the puppies will be black color as black is a dominant trait.

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