A card is drawn randomly from a standard 52-card deck. then the probabilities are a) 1/13 b) 3/13 and c) 10/13
There are four 3's in the deck. This means that, from 52 possible cards to drawn, we have 4 chances of drawing a 3. This means that the probability will be:
p = 4/52
p= 1/13
b.
For every suit, there are three face cards, J, Q and K. There are 4 suits, so, the total number of face cards its:
4*3 =12
The total possible cards are, still, 52, so, the probability will be
p= 12/52
p=3/13
c.
We know that the card drawn must be a face card, o not being a face card. There is no third choice here. So, the probability of drawing a face card OR not drawing a face card its:
p=52/52
p=1
so
p( the card is a face card ) + p( the card is not a face card) =1
but, we know that
p( the card is a face card ) =3/13
so
p( the card is not a face card) =1- 3/13
= 10/13
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