a rectangular piece of metal is 10 in longer than it is wide. squares with sides 2 in long are cut from the four corners and the flaps are folded upward to form an open box. if the volume of the box is 671 in, what were the original dimensions of the piece of metal?

The term “volume” refers to the amount of three-dimensional space taken up by an item or a closed surface. It is denoted by V and its SI unit is in cubic cm.

Dimension of the rectangle;

Width(w)

Length,L= 10 + w

volume of the box = length * width * height

Dimension of the box;

length of box, (x + 10) - 4 = x + 6

width of box,(x - 4)

height of box = 2

The volume of the box is 672 in³;

⇒V=lwh

⇒V=2 (x -4)( x + 6)

⇒672 in³ = 2x² + 4x - 48

⇒2x² + 4x - 720 = 0

⇒x^2 + 2x - 360 = 0

⇒(x +20)(x - 18) = 0

⇒x = 18

⇒x=-20 (value of the dimension will not be negative.

The width of an original piece of metal is;

Width,w=18 inches

length,l= 28 inches

Hence. the length and width of the piece of metal are 28 and 18 inches respectively.

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a rectangular piece of metal is 10 in longer than it is wide. squares with sides 2 in long are cut from the four corners and the flaps are folded upward to form an open box. if the volume of the box is 671 in​, what were the original dimensions of the piece of​ metal?

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a rectangular piece of metal is 10 in longer than it is wide. squares with sides 2 in long are cut from the four corners and the flaps are folded upward to form an open box. if the volume of the box is 671 in, what were the original dimensions of the piece of metal?