Respuesta :
Using the ideal gas law equation, the gas pressure of helium becomes 0.6atm when the volume increases to 2[tex]m^3[/tex].
The general gas equation, often known as the ideal gas law, is the equation of state for a fictitious ideal gas. Although it has several restrictions, it is a decent approximation of the behaviour of numerous gases under various circumstances.
According to the ideal gas law, all gases have an equal number of molecules in an equal volume at a given temperature and pressure.
Ideal gas law:
PV = nRT
where,
P – Pressure
V – Volume
n – No. of moles
R – Gas constant
T - Time
Given:
V1 = 1[tex]m^3[/tex]
P1 = 1.2atm
V2 = 2[tex]m^3[/tex]
To find:
P2 = ?
Formula:
PV = nRT
Calculations:
PV/T = constant
P1V1/T1 = P2V2/T2
Since T1 = T2,
P1V1 = P2V2
1.2 x 1 = P2 x 2
P2 = 1.2 x 1 / 2
P2 = 0.6atm
Result:
The gas pressure of helium becomes 0.6atm when the balloon rises high and the volume increases to 2[tex]m^3[/tex].
The complete question is:
a helium gas balloon has a volume of 1[tex]m^3[/tex] and a gas pressure of 1.2atm. when it is high in the sky, the volume increases to 2[tex]m^3[/tex]. assuming the gas temperature does not change and there is no gas leakage, the gas pressure becomes _____atm.
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