ow many moles of the precipitate, agcl (s), will form if 9.11 g of cacl2 is used to react with excess amounts of agno3? the molar mass of cacl2 is 110.98 g/mol. report the answer to the second decimal place. the balanced chemical reaction is : 2agno3 (aq) cacl2 (aq) ⟶2 agcl (s) ca(no3)2 (aq)

Respuesta :

By using the no. of moles, the mass of AgCl formed is determined to be 23.50g.

The mass of a material that includes the substance's particles is referred to as a mole.

The number of moles of a material equals to the ratio of its given mass to the mass of one mole of that substance in a chemical reaction. A mole / the no. of moles of any substance is equal to Avogadro's number, which is 6.023 x [tex]10^{23}[/tex]. Additionally, no. of moles is employed to represent concentration measurements like mole per liter and molecular weight.

[tex]2AgNO_3 (aq) + CaCl_2 (aq) \rightarrow 2AgCl (s) + Ca(NO_3)_2 (aq)[/tex]

Since [tex]AgNO_3[/tex] is in excess, the amount of product formed will be decided by the quantity of [tex]CaCl_2[/tex], which is the limiting reagent.

1 mole of [tex]CaCl_2[/tex] produces 2 moles of AgCl

No. of moles of [tex]CaCl_2[/tex] = mass of [tex]CaCl_2[/tex] / molar mass of [tex]CaCl_2[/tex]

No. of moles of [tex]CaCl_2[/tex] = 9.11 / 110.98 = 0.0820 moles

No. of moles of AgCl formed = 2 x 0.0820 = 0.164 moles

Mass of AgCl formed = No. of moles x molar mass

Mass of AgCl formed = 0.164 x 143.3 = 23.5012g

Result:

23.50g of AgCl is formed.

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