Respuesta :
The oxidation number of S in [tex]SO_4^{2-}[/tex] is + 6 and C in [tex]C_2O_4^{2-}[/tex] is + 3.
The charge an atom would have if it were an ion in the molecule is what is known as the oxidation number of that atom. An atom in a neutral compound made up entirely of atoms of one element has an oxidation number of 0.
The oxidation number, sometimes referred to as the oxidation state, is the total number of electrons that an atom gains or loses in order to form a chemical bond with another atom.
The loss of negatively charged electrons causes an increase in oxidation number, whereas the addition of electrons causes a decrease in oxidation number. The oxidized element or ion's oxidation number increases as a result.
Oxygen's oxidation number, O = - 2.
Use:
4 x oxidation number (O) + 1 x oxidation number (S) = net charge
4 x (-2) + 1 x (S) = - 2
- 8 + S = - 2
S = + 6
So, oxidation number of S in [tex]SO_4^{2-}[/tex] = + 6
Oxygen's oxidation number, O = - 2.
Use:
4 x oxidation number (O) + 2 x oxidation number (C) = net charge
4 x (-2) + 2 x (C) = - 2
- 8 + 2C = - 2
2C = + 6
C = + 3
So, the oxidation number of C in [tex]C_2O_4^{2-}[/tex] = + 3
Learn more about Oxidation number here:
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