how many moles and how many ions of each type are present in each of the following? (a) 88 ml of 1.75 m magnesium chloride (b) 321 ml of a solution containing 0.22 g aluminum sulfate/l (c) 1.65 l of a solution containing 8.83×1021 formula units of cesium nitrate per liter

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contexto115 contexto115 · Answer 1 · 2022-10-16T13:40:36+02:00

a. The number of moles = 0.154 moles and number of ions =2.78x10²³ ions.

b. The number of moles= 2.18x10⁻⁴ moles and number of ions = 6.56x10²⁰ ions.

c. The number of moles= 0.0147 moles and number of ions = 1.77x10²² ions .

Calculation of the no of moles and no of ions:

A. Moles MgCl₂:

According to question

88mL = 0.088L * (1.75mol / L) = 0.154 moles MgCl₂

By using (Avogadro's number:)

So,

0.154mol *(6.022x10²³ molecules / 1 mol) = 9.27x10²² molecules.

Since 1 molecule of MgCl₂ contains 3 ions:

So,

Ions = 2.78x10²³

B. Moles Al₂(SO₄)₃:

( Aluminum sulfate , molar mass = 324.15g/mol:)

So,

0.321L * (0.22g Al₂(SO₄)₃ / L) * (1mol / 324.15g) = 2.18x10⁻⁴ moles.

Now,

1 molecule contains 5 ions:

So,

2.18x10⁻⁴ moles *(6.022x10²³ molecules / 1 mol) * 5 = 6.56x10²⁰ ions.

C. Since

8.83x10²¹ formula units of CsNO₃ = Number of molecules. Ions are:

So,

8.83x10²¹ * 2 = 1.77x10²² ions

And moles are:

8.83x10²¹ Formula units * (1mol / 6.022x10²³) = 0.0147 moles

learn more about moles here: brainly.com/question/24817060

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