The heat generated within the wire is 1.05 x 10¹⁰ W/m³ with a maximum temperature of 589.5 K.
Heat is the energy that has a correlation with the resistivity of the material. Resistivity depends on the resistance and wire dimension where the resistance of the material can be written as
R = ρ.L/A
where R is resistance, ρ is resistivity, L is the length of the wire and A is surface area.
The given parameters from this question are
σ = 14 W/m.K
ρ = 45 x 10¯⁸ Ωm
I = 120 A
d = 1 mm
r = 0.5 mm = 5 x 10¯⁴ m
Calculate the surface area
A = πr²
A = π(5 x 10¯⁴)²
A = 7.86 x 10¯⁷ m²
In 1 m³, the length of wire should be
V = A . L
1 = 7.86 x 10¯⁷ . L
L = 1272727.273 m
Find the resistance of wire per m³
R/V = ρ.L/A
R/V = 45 x 10¯⁸ . 1272727.273 / 7.86 x 10¯⁷
R/V = 728925.62 Ω/m³
Find the heat generated per m³ by using power
P/V = I² . R
P/V = 120² . 728925.62
P/V = 1.05 x 10¹⁰ W/m³
Find the heat generated per m by using power
P/L = P/V
P/L = P/V . A
P/L = 1.05 x 10¹⁰ . 7.86 x 10¯⁷
P/L = 8253 W/m
Find the maximum temperature
T = (P/L) / σ
T = 8253 / 14
T = 589.5 K
Find more on heat at : https://brainly.com/question/19666326
#SPJ4