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a portion of the keystone pipeline connecting oil production in canada and refining in the united states consists of a 0.76 m diameter pipe that carries 500,000 bbl of crude oil per day over a distance of 1744 km. calculate the average velocity (in m/s) of the oil in the pipe. hint: 500,000 bbl of oil has a volume of (500,000 bbl)×(158.97 l/bbl)/(1000l/m^3)

Respuesta :

The average velocity (in m/s) of the oil in the pipe is 2.04m/s.

What is the velocity?

It should be noted that from the information, the oil that is transported on a day = 500000 bbl. Based on the information given, this is equal to 79491.256 cubic meter.

It should be noted that the flow rate will be calculated as:

= Oil transported / Time taken

= 79491.256 / (24 × 60 × 60)

= 0.92m³ per second

It should be noted that the area will be calculated as:

A = πr²

where

π = 3.14

r = radius = Diameter / 2 = 0.76/2 = 0.38

Area = πr² = 3.14 × (0.34)² = 0.45m²

Now, the velocity will be calculated thus:

= Flow rate / Area

= 0.92 / 0.45

= 2.04m/s

In conclusion, the velocity is 2.04m/s.

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