By cross multiplying the given equation, we have
[tex]6x=(x-2)(x+8)[/tex]
By multiplying the right hand side, we get
[tex]6x=x^2+6x-16[/tex]
Then, by subtracting 6x to both sides, we have
[tex]0=x^2-16[/tex]
or equivalently,
[tex]x^2-16=0[/tex]
Since the left hand side is a conjugate binomial, it can be expressed as
[tex]x^2-16=(x+4)(x-4)[/tex]
Then, we have the equation
[tex](x+4)(x-4)=0[/tex]
Therefore, the values of x that make the equation true are x= 4 and x= -4
