iven:
he aangles of the stars;
Star A: p_A=0.67 arcsec
Star B: p_B=1.2 arcsec
Star C: p_C=0.35 arcsec
To find:xoplanation:
Order of the stars according to their distance.
he distacnce of a star in parsec is calculated using the formula,
[tex]D=\frac{1}{p}[/tex]
Where p is the angles made by the stars in arcseconds.
On substituting the known values:
Star A,
[tex]\begin{gathered} D_A=\frac{1}{p_A} \\ =\frac{1}{0.67} \\ =1.5\text{ parsec} \end{gathered}[/tex]
Star B,
[tex]\begin{gathered} D_B=\frac{1}{p_B} \\ =\frac{1}{1.2} \\ =0.83\text{ parsec} \end{gathered}[/tex]
Star C,
[tex]\begin{gathered} D_C=\frac{1}{p_C} \\ =\frac{1}{0.35} \\ =2.9\text{ parsec} \end{gathered}[/tex]
inal answer:
Thus the closest star is star B and the farthest star is star C.
Thus the correct answer is option B.