substitute the given values in the formula of (BAC) we have
[tex]48\cdot3.2\colon160-3\cdot0.015[/tex]
Remember
Applying PEMDAS
P ----> Parentheses first
E -----> Exponents (Powers and Square Roots, etc.)
MD ----> Multiplication and Division (left-to-right)
AS ----> Addition and Subtraction (left-to-right)
so
step 1
solve the multiplication
48*3.2=153.6
substitute
[tex]153.6\colon160-3\cdot0.015[/tex]
step 2
Solve the division
153.6/160=0.96
substitute
[tex]0.96-3\cdot0.015[/tex]
step 3
solve the multiplication
3*0.015=0.045
substitute
[tex]0.96-0.045[/tex]
step 4
solve the subtraction
0.96-0.045=0.915
