Given:
The car ride from Kiley's house to the airport.
Distance =24.3 miles.
Time =1/2 hour.
We know that
[tex]\text{Average rate =}\frac{\text{Distance}}{\text{time}}[/tex]
Substitute Distance =24.3 miles and time =1/2 hour to compute the average rate of the car ride from Kiley's house to the airport.
[tex]=\frac{24.3\text{ miles}}{\frac{1}{2}\text{hours}}[/tex][tex]\text{ Use }\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a}{b}\times\frac{d}{c}\text{.}[/tex]
[tex]=24.3\times\frac{2}{1}\text{ miles per hour}[/tex]
[tex]=24.3\times2\text{ miles per hour}[/tex][tex]=48.6\text{ miles per hour}[/tex]
Hence the average rate of the car ride from Kiley's house to the airport is 48.6 miles per hour.
2)
Given that they walked 3/4 hours to the waiting area and covered the distance of 1.2 miles.
Distance =1.2 miles.
Time =3/4 hours.
we know that
[tex]\text{Average rate =}\frac{\text{Distance}}{\text{time}}[/tex]
Substitute distance =1.2 miles and time =3/4 hours to compute the average rate of the walk from the car to the waiting area by the gate, at the airport.
[tex]=\frac{1.2\text{ miles}}{\frac{3}{4}\text{ hours}}[/tex]
[tex]=1.2\times\frac{4}{3}\text{ miles per hour.}[/tex]
[tex]=\frac{1.2\times4}{3}\text{ miles per hour.}[/tex]
Multiplying 1.2 and 4, we get 4.8
[tex]=\frac{4.8}{3}\text{ miles per hour.}[/tex]
Dividing 4.8 by 3, we get 1.6
[tex]=1.6\text{ miles per hour.}[/tex]
Hence at the airport, the average rate of the walk from the car to the waiting area by the gate is 1.6 miles per hour.