Answer:
Use conversion:
[tex]1 joule = 1 kg m^2/s^2[/tex]
As per the given statement:
Mass of the skier(m) = 60 kg
height of the slope(h) = 10m/s
Speed(v) = 10m/s
By conservation of Energy states the law of conservation of energy states that the total energy of an isolated system remains constant.
[tex]P.E - K.E + E = 0[/tex]
P.E(Potential Energy) = mgh
K.E(Kinetic Energy)=[tex]\frac{1}{2}mv^2[/tex]
E represents the energy lose due to friction.
then;
[tex]mgh -\frac{1}{2}mv^2 + E = 0[/tex]
Substitute the given values;
Use [tex]g = 9.8 m/s^2[/tex]
then;
[tex](60)(9.8)(10) -\frac{1}{2}(60)(10)^2 + E = 0[/tex]
Simplify:
[tex]5880-3000+E = 0[/tex]
[tex]2880+E =0[/tex]
or
[tex]E = -2880 kgm^2/s^2[/tex]
Therefore, the energy does she lose to friction is 2880 joule
