One bag contains three white marbles and five black marbles, and a second bag contains four white marbles and six black marbles. A person draws one marble from each bag. Find the probability that both marbles are black.

Respuesta :

5/8 the first bag and 3/5 for the second bag.

Answer: [tex]\dfrac{3}{8}[/tex]

Step-by-step explanation:

Formula for probability :-

[tex]\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}[/tex]

Given : One bag contains 3 white marbles and 5 black marbles, and a second bag contains 4 white marbles and 6 black marbles.

Probability of drawing a black marble from first bag [tex]P(B_1=)\dfrac{5}{5+3}=\dfrac{5}{8}[/tex]

Probability of drawing a black marble from second bag [tex]P(B_2)=\dfrac{6}{6+4}=\dfrac{6}{10}[/tex]

Since the event of drawing marbles from each bag is independent, then

If a person draws one marble from each bag, then the probability that both marbles are black will be the product of both events :-

[tex]P(B_1)\times P(B_2)\\\\=\dfrac{5}{8}\times\dfrac{6}{10}=\dfrac{3}{8}[/tex]

Hence, the required answer = [tex]\dfrac{3}{8}[/tex]