This figure consists of a rectangle and a quarter circle. What is the perimeter of this figure? Use 3.14 for π . Enter your answer as a decimal in the box. please help giving away lots of points
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Answer:
[tex]61.27\ cm[/tex]
Step-by-step explanation:
we know that
The perimeter of the figure is equal to the perimeter of the rectangle plus the circumference of a quarter circle
so
Find the perimeter of the rectangle
The perimeter of rectangle is equal to
[tex]P=2(L+W)[/tex]
we have
[tex]L=20\ cm[/tex]
[tex]W=2\ cm[/tex]
substitute
[tex]P=2(20+2)=44\ cm[/tex]
Find the circumference of a quarter circle
[tex]C=\frac{1}{4}2\pi r[/tex]
we have
[tex]r=11\ cm[/tex]
substitute
[tex]C=\frac{1}{4}*2*(3.14)*(11)=17.27\ cm[/tex]
Find the perimeter of the figure
[tex]44\ cm+17.27\ cm=61.27\ cm[/tex]
Answer:
59.28 cm
Step-by-step explanation:
The perimeter of the shape is given by the formula:
Let the perimeter of the rectangle be P = 2 (20+ 2)
= 84 cm
The perimeter of the quarter circle be = [tex]\frac{1}{4} (\pi * 22)[/tex]
= 17.28 cm
Total perimeter = 20 + 2 + 9 + 11 + 17.28
= 59.28 cm