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An unknown force is applied to a 12 kg. The force acts at an angle of 30 degrees above the horizontal. Determine the force acting if the force acts for a horizontal displacement of 22 meters and increases the 12 kg mass's speed from 11 m/s to 26 m/s

Respuesta :

Time it take to displace to 22 m :

D     =  0.5 (Vi-Vf) t
22m = 0.5  ( 11+ 26)t
      t = 1.189 s

Acceleration

22m    = vt + 0.5at^2
a         = 12.616 m/s^2

F = ma

F sin 30 = 12 kg x 12.616 m/s^2

F = 302.805 N

 
onyebuchinnaji

The magnitude of the applied force is 174.7 N.

Acceleration of the mass

The acceleration of the mass is calculated as follows;

[tex]v^2 = u^2 + 2as\\\\a = \frac{v^2 - u^2}{2s} \\\\a = \frac{26^2 - 11^2}{2(22)} \\\\a = 12.61 \ m/s^2[/tex]

The applied force on the mass

The magnitude of the applied force is calculated as follows;

[tex]Fcos(\theta) = ma\\\\F = \frac{ma}{cos\theta} \\\\F = \frac{12 \times 12.61}{cos(30)} \\\\F = 174.7 \ N[/tex]

Thus, the magnitude of the applied force is 174.7 N.

Learn more about applied force here: https://brainly.com/question/14428983

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