Respuesta :
length of Roberts wire --- x
length of Maria's wire ---- 10-x
x = (2/3)(10-x)
times 3
3x = 2(10-x)
3x = 20 - 2x
5x = 20
x = 4
length of Maria's wire ---- 10-x
x = (2/3)(10-x)
times 3
3x = 2(10-x)
3x = 20 - 2x
5x = 20
x = 4