Vivian is making a rectangular wooden picture frame that will have a width that is 10 inches shorter than its length. If she will use 92inches of wood, what are the demensions of the frame?

Respuesta :

The width would be 41 inches and the length would be 51 inches. They both add up to 92 and the length is ten inches more!
notice the picture included, thus

[tex]\bf Area=A=length\cdot width \begin{cases} length = L\\ width = W=L-10\\ Area = A = 92 \end{cases} \\\\ 92=L(L-10)\impliedby \textit{solve for "L"}[/tex]

what's the width? well, W = L - 10
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