Respuesta :

texaschic101
1/3a - 5 - (1/6a + 3) = 
1/3a - 5 - 1/6a - 3 =
1/3a - 1/6a - 5 - 3 =
2/6a - 1/6a - 8 =
1/6a - 8 <===
kudzordzifrancis

Answer:

[tex]\frac{3a+8}{3(2a+1)(3a-5)}[/tex]

Step-by-step explanation:

We want to subtract [tex]\frac{1}{6a+3}[/tex] from [tex]\frac{1}{3a-5}[/tex].


We set up the subtraction problem as follows;


[tex]\frac{1}{3a-5}-\frac{1}{6a+3}[/tex]


We collect LCM of the denominators to obtain


[tex]=\frac{6a+3-(3a-5)}{(6a+3)(3a-5)}[/tex]


Expand the bracket in the numerator to obtain;


[tex]=\frac{6a+3-3a+5}{(6a+3)(3a-5)}[/tex]


This simplifies to;


[tex]=\frac{3a+8}{3(2a+1)(3a-5)}[/tex]


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