Answer:
c.68
Step-by-step explanation:
We are given that
[tex] sin(x-20)=cos 42^{\circ}[/tex] Where 0 <x< 90
We have to solve for x
[tex]sin(x-20)=cos (90-48)[/tex]
[tex] sin(x-20)=sin 48[/tex]
[tex] cos (90-\theta)=sin\theta[/tex]
Cancel sin on both sides then we get
[tex]x-20=48[/tex]
[tex]x=48+20=68[/tex]
Hence, the value of x=68
Answer:c.68
