Answer:
[tex]3\frac{1}{2} < 3\frac{19}{20} < 3\frac{39}{40}[/tex]
Step-by-step explanation:
Given numbers,
[tex]3\frac{39}{40}, 3\frac{19}{20}, 3\frac{1}{2}[/tex]
[tex]=\frac{159}{40}, \frac{79}{20}, \frac{7}{2}[/tex]
Since, LCM( 40, 20, 2 ) = 40,
So, we need to make denominator 40 of all fractions for comparing them,
[tex]\frac{159}{40}, \frac{158}{40}, \frac{140}{40}[/tex]
We know that,
[tex]\frac{140}{40} < \frac{158}{40} < \frac{159}{40}[/tex]
[tex]\implies 3\frac{1}{2} < 3\frac{19}{20} < 3\frac{39}{40}[/tex]
Which is the required order.
