Respuesta :
Vcone=(1/3)hpir^2
d/2=r
18/2=d/2=9=r
h=18
v=(1/3)(18)(pi)(9^2)
V=(6)(pi)(81)
V=486pi
V=1526.04 ft³
d/2=r
18/2=d/2=9=r
h=18
v=(1/3)(18)(pi)(9^2)
V=(6)(pi)(81)
V=486pi
V=1526.04 ft³
The volume of the space in the cone-shaped attic tower which has diameter 18 ft and heigth 18 ft is 1526.04 ft³.
What is of volume of solid?
Volume of solid is the amount of quantity, which is obtained by the solid or object in the 3 dimensional space.
The volume of the cone is given as,
[tex]V=\dfrac{1}{3}\pi r^2h[/tex]
Here (r) is the radius of the cone and (h) is the height of the cone.
The diameter of the attic is 18 ft. As the radius of cone is half of its diameter. Thus the radius of the cone is,
[tex]r=\dfrac{18}{2}\\r=9\rm ft[/tex]
The tower has a cone-shaped attic. The radius of this tower is 9 ft and its height is 18 ft. Thus, find its volume by plug in the values in the above formula as,
[tex]V=\dfrac{1}{3}\pi (9)^2(18)\\V=\dfrac{1}{3}\times3.14\times (9)^2(18)\\V=1526.04\rm ft^3[/tex]
Thus, the volume of the space in the cone-shaped attic tower which has diameter 18 ft and heigth 18 ft is 1526.04 ft³.
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