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A weather balloon slowly expands as energy is transferred as heat from the outside If the average net pressure is air. 1.5 x 103 Pa and the balloon's volume increases by 5.4 x 10 5 m how much work is done by the expanding gas? What thermodynamic process does this situation resemble?

Respuesta :

IthaloAbreu

Answer:

8.1x10⁸ J

A pressure constant process.

Explanation:

The gas inside the balloon is gain heat from the surroundings and its volumes increase, but the pressure remains constant. So, it's a pressure constant process.

For this thermodynamic process, the work is the pressure multiplied by the volume variation:

W = 1.5x10³ x 5.4x10⁵

W = 8.1x10⁸ J

pstnonsonjoku

The work done by the gas is 8.1  x 10^6 Pam^3.

We know that the work done in expanding a gas is given by the formula;

w = PΔV

w = work done

P = pressure of the gas

V = volume of the gas

Now;

P = 1.5 x 10^3 Pa

V = 5.4 x 10^5 m^3

w = 1.5 x 10^3 x  5.4 x 10^5 m^3

w = 8.1  x 10^6 Pam^3

Learn more about work done by a gas: https://brainly.com/question/17192821

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