For a parallel structure of identical​ components, the system can succeed if at least one of the components succeeds. Assume that components fail independently of each other and that each component has a 0.11

​(a) Would it be unusual to observe one component​ fail?

Would it be unusual to observe two components​ fail?

​(b) What is the probability that a parallel structure with 2 identical components will​ succeed?

The probability that a parallel structure with 2 identical components will succeed is
​(Type an integer or a decimal. Do not​ round.)

​(c) How many components would be needed in the structure so that the probability the system will succeed is greater than​ 0.9999?

​(Round up to the nearest whole​ number.)

Respuesta :

1) If you ever come across a situation where components fail independently of each other and that each component has a 0.11 it won'be unsusual because such percent as 11% is quite frequent and common.

2) If 
two components​ fail, that will definitely be unusual as the percent greatly increases : 11%*11%=1,21% - it is not as common as in previous situation.

3) Here is the way how you can get the 
probability that a parallel structure with 2 identical components will succeed :
you have to take the obtained percent away from 100% 
100-1,21=98,79 

4) The number of 
components that  will be needed in the structure so that the probability the system will succeed is greater than .9999 is being shown below: 
[tex]12^n = .0001
 n = 4.34[/tex]
then just round it up.
Do hope that will help you!