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A spherical object has a diameter of 18 cm. It has a spherical inner core with a diameter of 9 cm.
What is the volume of the outer layer?
Use 3.14 to approximate pi. Round to the nearest hundredth if necessary.
Enter your answer in the box.

cm³

Respuesta :

The answer is 2670.57 (i just took the quiz so this is the answer for sure)

Answer:

The volume of the outer layer is 2670.57 cm³ .

Step-by-step explanation:

Formula

[tex]Volume\ of\ a\ sphere = \frac{4}{3} \pi r^{3}[/tex]

Where r is the radius of the sphere .

As given

A spherical object has a diameter of 18 cm.

It has a spherical inner core with a diameter of 9 cm.

Let us assume that the radius of the spherical object is represented by R .

Let us assume that the radius of the inner object is represented by r .

[tex]Diameter (R) = \frac{18}{2}[/tex]

                            = 9 cm

[tex]Diameter (R) = \frac{9}{2}[/tex]

                            = 4.5 cm

[tex]\pi = 3.14[/tex]

Volume of the outer layer = Volume of the spherical object - Volume of the inner core .

[tex]Volume\ of\ a\ outer\ layer = \frac{4}{3}\times 3.14\times 9\times 9\times 9 - \frac{4}{3}\times 3.14\times 4.5\times 4.5\times 4.5[/tex]

[tex]Volume\ of\ a\ outer\ layer = \frac{4\times 3.14\times 9\times 9\times 9}{3}- \frac{4\times 3.14\times 4.5\times 4.5\times 4.5}{3}[/tex]

[tex]Volume\ of\ a\ outer\ layer = \frac{9156.24}{3}- \frac{1144.53}{3}[/tex]

[tex]Volume\ of\ a\ outer\ layer = 3052.08-381.51[/tex]

[tex]Volume\ of\ a\ outer\ layer = 2670.57\ cm^{3}[/tex]

Therefore the volume of the outer layer is 2670.57 cm³ .