contestada

An 80.8 kg man is standing on a frictionless ice surface when he throws a 2.3 kg book at 11.8 m/s. With what velocity does the man
move across the ice?
VM= ? m/s in the opposite direction as the book

Respuesta :

The amount of velocity does the man move across the ice(V)= 1 m/s in the opposite direction as the book

How can we calculate the values of the velocity does the man

move across the ice?

To calculate the velocity we would be using the formula,

M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂

Here we are given that,

Apply the law of linear momentum

.

Before the throw:

M₁=Man mass= 80kg,

U₁=velocity = 0,

M₂=Book mass = 4kg,

U₂=velocity = 0.

After the throw:

M₁=Man mass = 80kg,

V₁=velocity = V.

M₂=Book mass = 4kg,

V₂=velocity = 20.

Now we put the values in the formula, we get,

M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂

Or, (80x0) + (4x0) = (80V) + (4x20)

Or, 0=80V + 80

Or, 80V = -80

Or, V = -80/80

Or, V= -1m/s.

From the above calculation we can conclude that,

The amount of velocity does the man move across the ice(V)= 1 m/s in the opposite direction as the book

[Note: The (-)Ve sign shows that the opposite direction]

Learn more about Velocity:

https://brainly.com/question/25749514

#SPJ9

Otras preguntas