The airplane that descends at a rate of 2,700 feet per minute, after 3 1/2 minutes it will be at 9450 ft
The formula and procedure we will use to solve this problem is:
v= x/t
Where:
Information about the problem:
Converting the mixed fraction to a fraction, we get:
3 1/2 =
[(3*2) + 1]/2 =
(6+1) / 2 =
7/2
3 1/2 min is equivalent to 7/2
Applying the velocity and isolating the distance we have:
x= v*t
x = 2700 ft/min * 7/2 min
x = 9450 ft
It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).
Learn more about velocity at: brainly.com/question/3004254
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