The coordinates of A'' will be ( -2, 5).
We are given that:
Quadrilateral ABCD is reflected across the x - axis.
We know that, when a refection is done about x-axis, the values of the abscissa x remain identical & the value of ordinate just change their signs:
A(-5,-3) will become A'(-5,+3)
B(-6,-1) will become B'(-6,+1)
C(-3,-1) will become C'(-3,+1)
D(-2,-3) will become D'(-2,+3)
Now, the reflected quadrilateral A'B'C'D' is then translated 3 units right and 2 units up to form quadrilateral A"B"C"D".
So, the coordinates of A'' will become:
( - 5 + 3, 3 + 2)
( -2, 5)
Therefore, we get that, the coordinates of A'' will be ( -2, 5).
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