An x-ray beam with wavelength 0. 210 nm is directed at a crystal. As the angle of incidence increases, you observe the first strong interference maximum at an angle 70. 0 ∘. What is the spacing d between the planes of the crystal?

Respuesta :

By using Bragg's diffraction, the spacing d is 0.112 nm.

We need to know about Bragg's diffraction to solve this problem. Bragg's diffraction is described how monochromatic light travels through a crystal medium. The monochromatic light should follow

2d.sin(θ) = λ

where d is the spacing between the planes of the crystal, θ is the incident light angle and λ is the wavelength.

From the question above, we know that

θ = 70⁰

λ = 0.210 nm = 0.21 x 10¯⁹ m

By substituting the given parameters, we get

2d.sin(θ) = λ

2d.sin(70⁰) = 0.21 x 10¯⁹

2d . 0.94 = 0.21 x 10¯⁹

d = 1.12 x 10¯¹⁰ m

d = 0.112 nm

For more on Bragg's diffraction at: https://brainly.com/question/13009361

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