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Calculate the average speed of a complete round trip in which the outgoing 290 km is covered at 91 km/h , followed by a 1.0- h lunch break, and the return 290 km is covered at 54 km/h .

Respuesta :

The average speed of the complete round trip is 61.12 km / h.

We need to know about the average speed to solve this problem. The average speed can be determined as the total distance divided by the total time. It can be written as

v = d / t

where v is average speed, d is distance and t is time.

From the question above, we know that

d1 = 290 km

v1 = 91 km/h

t lunch = 1 hour

d2 = 290 km

v2 = 54 km/h

Find the time during the outgoing

v1 = d1 / t1

t1 = d1 / v1

t1 = 290 / 93

t1 = 3.12 hours

Find the return time

v2 = d2 / t2

t2 = d2 / v2

t2 = 290 / 54

t2 = 5.37 hours

Hence, the total time

t = t1 + t2 + t lunch

t = 3.12 + 5.37 + 1

t = 9.49 hours

Find the average speed

v = d / t

v = (290 + 290) / 9.49

v = 61.12 km / h

For more on average speed at: https://brainly.com/question/24739297

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