hi can someone help me here
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Answer:
Step-by-step explanation:
[tex]\displaystyle\\F(6)\ \ \ \ \frac{15}{x-3} \\\\\frac{15}{6-3}= \\\\\frac{15}{3}= \\\\5\\\\F(a)\ \ \ \ \ \frac{15}{x-3} \\\\F(a)=\frac{15}{a-3}[/tex]
Answer:
5 and [tex]\frac{15}{a-3}[/tex]
Step-by-step explanation:
given
f(x) = [tex]\frac{15}{x-3}[/tex]
f(6) means what is the value of f(x) when x = 6
substitute x = 6 into f(x)
f(6) = [tex]\frac{15}{6-3}[/tex] = [tex]\frac{15}{3}[/tex] = 5
f(a) means what is the value of f(x) when x = a
substitute x = a into f(x)
f(a) = [tex]\frac{15}{a-3}[/tex]