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Consider two consecutive positive integers such that the square of the second integer added to 4 times the first is equal to 73.
Step 2 of 2 :
Find the integers by solving the equation.

Respuesta :

The numbers are 6 and 7.

How to solve the equation?

Let the values be x and x + 1.

Therefore, the equation will be:

4x + (x + 1)² = 73

4x + x² + 2x + 1 = 73

x² + 6x + 1 - 73 = 0

x² + 6x - 72 = 0

x² + 12x - 6x - 72

x(x + 12) - 6(x + 12)

Therefore, x - 6 = 0

x = 0 + 6 = 6

Therefore, the numbers are 6 and 7

Learn more about equations on:

brainly.com/question/2972832

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