contestada

If the probability of being hospitalized during a year is 0.25, find the probability that no one in a family of five will be
hospitalized in a year.

Respuesta :

varshamittal029

The probability that no one in a family of five will be hospitalized in a year 0.2373 .

  • Probability is a measure of the likelihood that an event will occur. Many events cannot be predicted with complete certainty. We can only predict the probability that an event will occur .Probabilities can range from 0 to 1. 0 means the event is not possible, 1 indicates the specific event.
  • The formula for probability is given by  P(E) + P'(E) = 1    ...(1) where P(E) is the event will happen

Let P(E) denote the probability of being hospitalized during a year and P'(E) the probability of not being hospitalized during a year

Then , using equation (1) , we get

          [tex]0.25+P'(E)=1\\P'(E)=1-0.25\\P'(E)=0.75[/tex]

The probability that no one in a family of five will be hospitalized in a year is equal to [tex](P'(E))^n[/tex] where n is the number of member .

   [tex](P'(E))^n=(0.75)^5\\(P'(E))^n=0.2373[/tex]

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