Find the perimeter when 121 triangles are put together in the pattern shown below. Assume that all triangle sides are 1 cm long.
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Applying the arithmetic sequence formula, the perimeter of the triangle is: 123 cm.
An arithmetic sequence formula is given as, T(n) = a + (n - 1)d, where a is the first term; n is the nth number of terms; d is the common difference.
Applying the arithmetic sequence formula to this problem, we have the following:
n = 121
a = 3
d = 1
Substitute
T(121) = 3 + (121 - 1)1
T(121) = 3 + (120)1
T(121) = 3 + 120
T(121) = 123
Therefore, applying the arithmetic sequence formula, the perimeter of the triangle is: 123 cm.
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