The volume a gas will occupy at a pressure of 0.940 atm and temperature of -15°C is 7.77 L (option B).
The volume of an ideal gas can be calculated using the combined gas law formula as follows:
P1V1/T1 = P2V2/T2
Where;
According to this question, a 8.25 L sample of oxygen is collected at 25°C and 1.022 atm pressure. The volume the gas will occupy at 0.940 atm and -15°C is as follows:
1.022 × 8.25/298 = 0.940 × V2/258
0.0283 × 258 = 0.940V2
7.299 = 0.940V2
V2 = 7.299 ÷ 0.940
V2 = 7.77 L
Therefore, the volume a gas will occupy at a pressure of 0.940 atm and temperature of -15°C is 7.77 L.
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