Line that passes through (0,-6) and (2,-4)
[tex]y = mx + c \\ m = \frac{ - 6 + 4}{0 - 2} = \frac{ - 2}{ - 2} = 1 \\ c = y - mx = - 4 - 1(2) = - 6 \\ y = x - 6[/tex]
If the third point (-3,-8) belongs to this line, then it must satisfy its equation and be collinear to the other two points, if not, then these points are not collinear, check:
[tex] - 8 = - 3 - 6 \\ - 8≠ - 9 \\ so \: nopeeee[/tex]
