a driver of a car took a day trip around the coastline driving at two different speeds. he drove 50 miles at a slower speed and 300​ miles at a speed 20 miles per hour faster. if the time spent driving at the faster speed was thrice that spent driving at the slower​ speed, find the two speeds during the trip.

Respuesta :

The slower speed is 20 miles per hour and the higher speed is 40 miles per hour.

time is calculated using the formula

[tex]Time=\frac{Distance}{Speed}[/tex]

In the given question

driver drove 50 miles at slower speed.

Let the slower speed be x miles per hour.

So the time taken to cover 50 miles at slower speed = [tex]\frac{50}{x}[/tex]    ...(i)

driver drove 300 miles at faster speed.

given speed is 20 miles per hour faster i.e. speed = (x+20) miles per hour So the time taken to cover 300 miles at (x+20) mph speed = [tex]\frac{300}{(x+20)}[/tex]....(ii)

According to the question

the time spent driving at the faster speed was thrice that spent driving at the slower​ speed.

From equation (i) and (ii) we get

[tex]3*(\frac{50}{x} )=\frac{300}{x+20}[/tex]

[tex]\frac{150}{x} =\frac{300}{x+20}[/tex]

Cross Multiplying we get

[tex]150(x+20)=300x\\ \\ 150x+3000=300x\\ \\ 300x-150x=3000\\ \\ 150x=3000\\ \\ x=20[/tex]

Slower speed = x = 20mph.

Faster speed = (x+20) = 20+20 = 40mph.

Therefore , The slower speed is 20 miles per hour and the higher speed is 40 miles per hour.

Learn more about Speed, Time and Distance here  https://brainly.com/question/14975450

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