The equilibrium constant can be obtained using ΔG°rxn = -RT lnK.
On the basis of this, 2H+ + 2e- → H2(g) reduction.
Therefore E° = 0V
Pb2+ + 2e- ⇄ Pb(s) - 0.126
Mg2+ + 2e- ⇄ Mg(s) -2.372
For total E°cell potential,
E°cell = Ered - Eoxd
Eoxd = -Ered of the one being oxidised
E°cell = -2.372 - (-0.126) = -2.246
E°cell = -2.246 V
Thus, calculating dG:
dG = -n x F x E°cell
dG = -2*96500*(-2.246)
=433478 J/mol
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