Respuesta :
The time the ball spend on the air before reaching the ground is 2.325 seconds.
The kinematic formula would be most useful to solve for the target unknown is
H = ut + ½gt²
Basket ball is drop from height
H=10m
It is dropped on planet mass
And the acceleration due to gravity on Mars is given as
g= 3.7m/s²
Time taken for the ball to reach the ground
Initial velocity of the body is zero
u=0m/s
Using equation of motion: free fall
H = ut + ½gt²
10 = 0•t + ½ × 3.7 ×t²
10 = 0 + 1.85t²
10 = 1.85t²
Then, t² =10/1.85
t² = 5.405
t = √ 5.405
t = 2.325seconds
So the time the ball spend on the air before reaching the ground is 2.325 seconds.
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Onur drops a basketball from a height of 10 m on Mars, where the acceleration due to gravity has a magnitude of 3.7 m/s². We want to know how many seconds the basketball is in the air before it hits the ground.
Which kinematic formula would be most useful to solve for the target unknown?
Answer: Δy = v0t - ½ at²
