The equation of the line shown in the reference graph, attached hereby, that passes through the points (-6, 0) and (0, 4) is [3y = (2x + 12)].
As per the question statement, we are provided with a straight line, drawn on the cartesian quadrants that pass through two points, (-6, 0) and (0, 4).
We are required to determine the equation of the line.
To solve this question, we need to know the formula to determine the linear equation of a line passing through two points, (x₁, y₁) and (x₂, y₂), which goes as [tex][(y-y_{1})=(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}) (x-x_{1})][/tex].
Here, let us consider, (-6, 0) to be (x₁, y₁), and (0, 4) to be (x₂, y₂). Therefore, using these values in the above mentioned equation, we get
[tex](y-0)=[\frac{4-0}{0-(-6)}][x-(-6)]\\ or, y=(\frac{4}{6})(x+6)\\ or, y=(\frac{2}{3})(x+6)\\or, 3y=2x+12[/tex]
- Equation: An equation is a mathematical statement having two separate expressions, connected by an equal sign
- Line: A line is an one-dimensional figure, having infinite length but no width.
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https://brainly.com/question/1971145
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