Brian has money into savings accounts. One rate is 11% and the other is 15%. If he has $900 more in the 15% account and a total of interest of $213 how much is invested in each savings account?

Respuesta :

The amount invested at 15% was $900 whereas the $300 was invested in the 11% account

How do we represent the amounts invested in each account?

The fact that $900 more was invested in 15% account means that if the amount invested in the 11% is x, then amount in the other would be x+900

interest on 15% account=15%*(x+900)

interest on 15% account=0.15x+135

interest on 11% account=11%*x=0.11x

total interest=0.15x+135+0.11x

total interest on both accounts=0.26x+135

total interest earned=$213

213=0.26x+135

213-135=0.26x

78=0.26x

x=78/0.26

x=$300(amount invested in the 11% account)

amount invested in the 15% account=$300+$900

amount invested in the 15% account=$1200

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