The vapor pressure is obtained as 3.7 atm.
The Clausius-Clapeyron equation is the equation that we could use to obtain the vapor pressure of a solution at any temperature. Of course we would always have two different temperatures to work with.
Hence;
ln(P1/P2) = ΔHvap/R (1/T2 - 1/T1)
P1 = initial pressure
P2 = final pressure
ΔHvap = enthalpy of vaporization
T2 = final temperature
T1 = initial temperature
ln(1/P2) = 35.2 * 10^3/8.314 (1/338 - 1/307)
ln(1/P2) = 4234(0.00295 - 0.00326)
ln(1/P2) = -1.31
1/P2 = e^-1.31
P2 = 1/e^-1.31
P2 = 3.7 atm
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