Respuesta :
The amount of CO2 is produced is 60.28 g
In this combustion reaction , O2 act as a limiting reagent
96.0 g O2 = 3.0 mol O2 is present for the combustion reaction.
In the combustion reaction 60.4 g of water is formed
60.4 g of Water = 60.4 g * 1 mol / 18 g = 3.35 mol
3.35 mol of H20 has 6.32 mol of H atoms.
If hydrocarbon acts like limiting reactant , then 35.5 - 6.32 g of carbon = 29.18 g that is equal to 2.12 mol.
2.12 mol of C requires 2.12 mol * 2 = 4.24 mol of atoms to burn completely O atoms.
3.35 mol of H2O atom + 4.24 of O atoms = 7.59 mol. So, O2 is a limiting reactant.
3.35 mol of O2 atoms are in H2O , 6 - 3.35 = 2.65 mol of O2 atoms are there in CO2. Hence 1.37 mol of CO2 is going to produced.
Mass of CO2 produced = 1.37 * 44 = 60.28 g
By the law of conservation mass we found that 19.13 g of hydrocarbons remains unburnt.
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