On a day when the wind is blowing towards the south at 7 m/a, a runner jogs west at 7 m/s. what is the velocity (speed and direction) of the air relative to the runner?

Respuesta :

Given,

Velocity of the wind = 7 m/s

Velocity of Runner = 7 m/s

Since velocity is a vector quantity

So the magnitude for the resultant vector can be calculated by using the formula [tex]\sqrt{x^{2} +y^{2} }[/tex], where x is the magnitude of the x-axis component and y is the magnitude of the y-axis component

i.e.

= [tex]\sqrt{7^{2} +7^{2} }[/tex];

= [tex]\sqrt{49+49}[/tex]

= [tex]\sqrt{98}[/tex]

= 9.8 m/s

Also the direction can be calculated by

[tex]\beta[/tex] = Tan⁻([tex]\frac{7}{7}[/tex])

[tex]\beta[/tex] = 45°

The angle between the resultant velocity and the horizontal axis is 45° i.e. SOUTH-WEST direction.

ANS: The velocity of the air relative to the runner will be 9.8 m/s in South-West direction.

To know more about vector quantity,

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