Given,
Velocity of the wind = 7 m/s
Velocity of Runner = 7 m/s
Since velocity is a vector quantity
So the magnitude for the resultant vector can be calculated by using the formula [tex]\sqrt{x^{2} +y^{2} }[/tex], where x is the magnitude of the x-axis component and y is the magnitude of the y-axis component
i.e.
= [tex]\sqrt{7^{2} +7^{2} }[/tex];
= [tex]\sqrt{49+49}[/tex]
= [tex]\sqrt{98}[/tex]
= 9.8 m/s
Also the direction can be calculated by
[tex]\beta[/tex] = Tan⁻([tex]\frac{7}{7}[/tex])
[tex]\beta[/tex] = 45°
The angle between the resultant velocity and the horizontal axis is 45° i.e. SOUTH-WEST direction.
ANS: The velocity of the air relative to the runner will be 9.8 m/s in South-West direction.
To know more about vector quantity,
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