The distance between you and the deer when you come to a stop is
s = d - 30 = 18 m.
The maximum speed you could have and still not hit the deer is
v = -5 + [tex]\sqrt{5}[/tex][tex]\sqrt{5 + 4d}[/tex]
= 26m/s
You're driving down the highway late one night at 20m/s when a deer steps onto road d in front of you.
Your reaction time before stepping on the brakes is 0.50s and the maximum deceleration of your car is 10m/s2.
Given,
Speed = 20m/s
Time = 0.50 s
Distance = d
Deceleration = 10m/s2
D = R × T
D = Vi × Tr
D = (20 m/s) × (0.50 s)
D = 10 m
Dd = [ Vf^2 - Vi^2 ] / [ 2 × (-10 m/s^2) ]
Dd = [ (0.0 m/s)^2 - (20 m/s)^2 ] / (-20 m/s^2)
Dd = [ -400 m^2/s^2 ] / (-20 m/s^2)
Dd = 20 m
The total distance traveled is
Dt = D + Dd
Dt = (10 m) + (20 m)
Dt = 30 m
The distance between you and the deer when you come to a stop is
s = d - 30 = 18 m.
The maximum speed you could have and still not hit the deer is
v = -5 + [tex]\sqrt{5}[/tex][tex]\sqrt{5 + 4d}[/tex]
= 26m/s
To learn more about speed, refer
https://brainly.com/question/13262646
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