The ball rises 53.361 m above the point where the bat hit the ball.
When a batter hits a ball high in a baseball game, the ball remains in the air for 6.6 seconds.
The acceleration of gravity is 9.8 m/s².
The vertex value of time is half of 6.6 seconds or 3.3 seconds.
Therefore, the final velocity at the maximum height is v = 0 m/s
Now, using the equation of motion:
v - u = gt
v = u + gt
u × sin(θ) = - gt
u × sin(θ) = 9.8 × 3.3
u × sin(θ) = 32.34 m/s
Now, by using the equation of motion:
v² - u² = 2gh
h = ( v² - u²) / 2g
h = ( 0 - (32.34)² ) / 2(9.8)
h = (1045.8756) / 19.6
h = 53.361 m
The ball rises 53.361 meter high.
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